break value targets a statement loop

Why this fires¶

A break carrying a value targets while or for. Only the unconditional loop form is a value-producing expression.

while ready() {
    break 1 // error[TE228]
}

Fix it¶

Remove the value, assign it before breaking, or use a value-producing loop.

let answer: int = loop {
    break 1
}

See also¶

• TE229 — break values disagree with a loop's result type.